sklearn.metrics.normalized_mutual_info_score

sklearn.metrics.normalized_mutual_info_score(labels_true, labels_pred, *, average_method='arithmetic') [source]

Normalized Mutual Information between two clusterings.

Normalized Mutual Information (NMI) is a normalization of the Mutual Information (MI) score to scale the results between 0 (no mutual information) and 1 (perfect correlation). In this function, mutual information is normalized by some generalized mean of H(labels_true) and H(labels_pred)), defined by the average_method.

This measure is not adjusted for chance. Therefore adjusted_mutual_info_score might be preferred.

This metric is independent of the absolute values of the labels: a permutation of the class or cluster label values won’t change the score value in any way.

This metric is furthermore symmetric: switching label_true with label_pred will return the same score value. This can be useful to measure the agreement of two independent label assignments strategies on the same dataset when the real ground truth is not known.

Read more in the User Guide.

Parameters

labels_trueint array, shape = [n_samples]

A clustering of the data into disjoint subsets.

labels_predint array-like of shape (n_samples,)

A clustering of the data into disjoint subsets.

average_methodstr, default=’arithmetic’

How to compute the normalizer in the denominator. Possible options are ‘min’, ‘geometric’, ‘arithmetic’, and ‘max’.

New in version 0.20.

Changed in version 0.22: The default value of average_method changed from ‘geometric’ to ‘arithmetic’.

Returns

nmifloat

score between 0.0 and 1.0. 1.0 stands for perfectly complete labeling

See also

v_measure_score

V-Measure (NMI with arithmetic mean option).

adjusted_rand_score

Adjusted Rand Index.

adjusted_mutual_info_score

Adjusted Mutual Information (adjusted against chance).

Examples

Perfect labelings are both homogeneous and complete, hence have score 1.0:

>>> from sklearn.metrics.cluster import normalized_mutual_info_score
>>> normalized_mutual_info_score([0, 0, 1, 1], [0, 0, 1, 1])
... 
1.0
>>> normalized_mutual_info_score([0, 0, 1, 1], [1, 1, 0, 0])
... 
1.0

If classes members are completely split across different clusters, the assignment is totally in-complete, hence the NMI is null:

>>> normalized_mutual_info_score([0, 0, 0, 0], [0, 1, 2, 3])
... 
0.0