SVM Tie Breaking Example
Tie breaking is costly if decision_function_shape='ovr'
, and therefore it is not enabled by default. This example illustrates the effect of the break_ties
parameter for a multiclass classification problem and decision_function_shape='ovr'
.
The two plots differ only in the area in the middle where the classes are tied. If break_ties=False
, all input in that area would be classified as one class, whereas if break_ties=True
, the tie-breaking mechanism will create a non-convex decision boundary in that area.
print(__doc__) # Code source: Andreas Mueller, Adrin Jalali # License: BSD 3 clause import numpy as np import matplotlib.pyplot as plt from sklearn.svm import SVC from sklearn.datasets import make_blobs X, y = make_blobs(random_state=27) fig, sub = plt.subplots(2, 1, figsize=(5, 8)) titles = ("break_ties = False", "break_ties = True") for break_ties, title, ax in zip((False, True), titles, sub.flatten()): svm = SVC(kernel="linear", C=1, break_ties=break_ties, decision_function_shape='ovr').fit(X, y) xlim = [X[:, 0].min(), X[:, 0].max()] ylim = [X[:, 1].min(), X[:, 1].max()] xs = np.linspace(xlim[0], xlim[1], 1000) ys = np.linspace(ylim[0], ylim[1], 1000) xx, yy = np.meshgrid(xs, ys) pred = svm.predict(np.c_[xx.ravel(), yy.ravel()]) colors = [plt.cm.Accent(i) for i in [0, 4, 7]] points = ax.scatter(X[:, 0], X[:, 1], c=y, cmap="Accent") classes = [(0, 1), (0, 2), (1, 2)] line = np.linspace(X[:, 1].min() - 5, X[:, 1].max() + 5) ax.imshow(-pred.reshape(xx.shape), cmap="Accent", alpha=.2, extent=(xlim[0], xlim[1], ylim[1], ylim[0])) for coef, intercept, col in zip(svm.coef_, svm.intercept_, classes): line2 = -(line * coef[1] + intercept) / coef[0] ax.plot(line2, line, "-", c=colors[col[0]]) ax.plot(line2, line, "--", c=colors[col[1]]) ax.set_xlim(xlim) ax.set_ylim(ylim) ax.set_title(title) ax.set_aspect("equal") plt.show()
Total running time of the script: ( 0 minutes 2.136 seconds)
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https://scikit-learn.org/0.24/auto_examples/svm/plot_svm_tie_breaking.html