tf.compat.v2.sparse.segment_sqrt_n
Computes the sum along sparse segments of a tensor divided by the sqrt(N).
tf.compat.v2.sparse.segment_sqrt_n(
    data, indices, segment_ids, num_segments=None, name=None
)
  Read the section on segmentation for an explanation of segments.
Like tf.sparse.segment_mean, but instead of dividing by the size of the segment, N, divide by sqrt(N) instead.
| Args | |
|---|---|
| data | A Tensorwith data that will be assembled in the output. | 
| indices | A 1-D Tensorwith indices intodata. Has same rank assegment_ids. | 
| segment_ids | A 1-D Tensorwith indices into the outputTensor. Values should be sorted and can be repeated. | 
| num_segments | An optional int32 scalar. Indicates the size of the output Tensor. | 
| name | A name for the operation (optional). | 
| Returns | |
|---|---|
| A tensorof the shape as data, except for dimension 0 which has sizek, the number of segments specified vianum_segmentsor inferred for the last element insegments_ids. | 
    © 2020 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
    https://www.tensorflow.org/versions/r1.15/api_docs/python/tf/compat/v2/sparse/segment_sqrt_n