std::invoke
Defined in header <functional> | ||
|---|---|---|
template< class F, class... Args> std::invoke_result_t<F, Args...> invoke(F&& f, Args&&... args) noexcept(/* see below */); | (since C++17) |
Invoke the Callable object f with the parameters args. As by INVOKE(std::forward<F>(f), std::forward<Args>(args)...).
where INVOKE(f, t1, t2, ..., tN) is defined as follows:
- If
fis a pointer to member function of classT: - If
std::is_base_of<T, std::decay_t<decltype(t1)>>::valueistrue, thenINVOKE(f, t1, t2, ..., tN)is equivalent to(t1.*f)(t2, ..., tN) - If
std::decay_t<decltype(t1)>is a specialization ofstd::reference_wrapper, thenINVOKE(f, t1, t2, ..., tN)is equivalent to(t1.get().*f)(t2, ..., tN) - If
t1does not satisfy the previous items, thenINVOKE(f, t1, t2, ..., tN)is equivalent to((*t1).*f)(t2, ..., tN). - Otherwise, if N == 1 and
fis a pointer to data member of classT: - If
std::is_base_of<T, std::decay_t<decltype(t1)>>::valueistrue, thenINVOKE(f, t1)is equivalent tot1.*f - If
std::decay_t<decltype(t1)>is a specialization ofstd::reference_wrapper, thenINVOKE(f, t1)is equivalent tot1.get().*f - If
t1does not satisfy the previous items, thenINVOKE(f, t1)is equivalent to(*t1).*f - Otherwise,
INVOKE(f, t1, t2, ..., tN)is equivalent tof(t1, t2, ..., tN)(that is,fis a FunctionObject)
Parameters
| f | - | Callable object to be invoked |
| args | - | arguments to pass to f |
Exceptions
noexcept specification: noexcept(std::is_nothrow_invocable_v<F, Args...>)Possible implementation
namespace detail {
template <class T>
struct is_reference_wrapper : std::false_type {};
template <class U>
struct is_reference_wrapper<std::reference_wrapper<U>> : std::true_type {};
template <class T>
constexpr bool is_reference_wrapper_v = is_reference_wrapper<T>::value;
template <class T, class Type, class T1, class... Args>
decltype(auto) INVOKE(Type T::* f, T1&& t1, Args&&... args)
{
if constexpr (std::is_member_function_pointer_v<decltype(f)>) {
if constexpr (std::is_base_of_v<T, std::decay_t<T1>>)
return (std::forward<T1>(t1).*f)(std::forward<Args>(args)...);
else if constexpr (is_reference_wrapper_v<std::decay_t<T1>>)
return (t1.get().*f)(std::forward<Args>(args)...);
else
return ((*std::forward<T1>(t1)).*f)(std::forward<Args>(args)...);
} else {
static_assert(std::is_member_object_pointer_v<decltype(f)>);
static_assert(sizeof...(args) == 0);
if constexpr (std::is_base_of_v<T, std::decay_t<T1>>)
return std::forward<T1>(t1).*f;
else if constexpr (is_reference_wrapper_v<std::decay_t<T1>>)
return t1.get().*f;
else
return (*std::forward<T1>(t1)).*f;
}
}
template <class F, class... Args>
decltype(auto) INVOKE(F&& f, Args&&... args)
{
return std::forward<F>(f)(std::forward<Args>(args)...);
}
} // namespace detail
template< class F, class... Args>
std::invoke_result_t<F, Args...> invoke(F&& f, Args&&... args)
noexcept(std::is_nothrow_invocable_v<F, Args...>)
{
return detail::INVOKE(std::forward<F>(f), std::forward<Args>(args)...);
}Example
#include <functional>
#include <iostream>
struct Foo {
Foo(int num) : num_(num) {}
void print_add(int i) const { std::cout << num_+i << '\n'; }
int num_;
};
void print_num(int i)
{
std::cout << i << '\n';
}
struct PrintNum {
void operator()(int i) const
{
std::cout << i << '\n';
}
};
int main()
{
// invoke a free function
std::invoke(print_num, -9);
// invoke a lambda
std::invoke([]() { print_num(42); });
// invoke a member function
const Foo foo(314159);
std::invoke(&Foo::print_add, foo, 1);
// invoke (access) a data member
std::cout << "num_: " << std::invoke(&Foo::num_, foo) << '\n';
// invoke a function object
std::invoke(PrintNum(), 18);
}Output:
-9 42 314160 num_: 314159 18
See also
|
(C++11) | creates a function object out of a pointer to a member (function template) |
|
(C++11)(removed in C++20)(C++17) | deduces the result type of invoking a callable object with a set of arguments (class template) |
|
(C++17) | checks if a type can be invoked (as if by std::invoke) with the given argument types (class template) |
|
(C++17) | calls a function with a tuple of arguments (function template) |
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