std::fmod, std::fmodf, std::fmodl
Defined in header <cmath> | ||
|---|---|---|
| (1) | ||
float fmod ( float x, float y ); | ||
float fmodf( float x, float y ); | (since C++11) | |
double fmod ( double x, double y ); | (2) | |
| (3) | ||
long double fmod ( long double x, long double y ); | ||
long double fmodl( long double x, long double y ); | (since C++11) | |
Promoted fmod ( Arithmetic1 x, Arithmetic2 y ); | (4) | (since C++11) |
x/y.double. If any other argument is long double, then the return type is long double, otherwise it is double.The floating-point remainder of the division operation x/y calculated by this function is exactly the value x - n*y, where n is x/y with its fractional part truncated.
The returned value has the same sign as x and is less than y in magnitude.
Parameters
| x, y | - | floating point values |
Return value
If successful, returns the floating-point remainder of the division x/y as defined above.
If a domain error occurs, an implementation-defined value is returned (NaN where supported).
If a range error occurs due to underflow, the correct result (after rounding) is returned.
Error handling
Errors are reported as specified in math_errhandling.
Domain error may occur if y is zero.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- If
xis ±0 andyis not zero, ±0 is returned - If
xis ±∞ andyis not NaN, NaN is returned andFE_INVALIDis raised - If
yis ±0 andxis not NaN, NaN is returned andFE_INVALIDis raised - If
yis ±∞ andxis finite,xis returned. - If either argument is NaN, NaN is returned
Notes
POSIX requires that a domain error occurs if x is infinite or y is zero.
std::fmod, but not std::remainder is useful for doing silent wrapping of floating-point types to unsigned integer types: (0.0 <= (y = std::fmod( std::rint(x), 65536.0 )) ? y : 65536.0 + y) is in the range [-0.0 .. 65535.0], which corresponds to unsigned short, but std::remainder(std::rint(x), 65536.0 is in the range [-32767.0, +32768.0], which is outside of the range of signed short.
The double version of fmod behaves as if implemented as follows.
double fmod(double x, double y)
{
#pragma STDC FENV_ACCESS ON
double result = std::remainder(std::fabs(x), (y = std::fabs(y)));
if (std::signbit(result)) result += y;
return std::copysign(result, x);
}The expression x - trunc(x/y)*y may not equal fmod(x,y) when the rounding of x/y to initialize the argument of trunc loses too much precision (example: x = 30.508474576271183309, y = 6.1016949152542370172).
Example
#include <iostream>
#include <cmath>
#include <cfenv>
#pragma STDC FENV_ACCESS ON
int main()
{
std::cout << "fmod(+5.1, +3.0) = " << std::fmod(5.1,3) << '\n'
<< "fmod(-5.1, +3.0) = " << std::fmod(-5.1,3) << '\n'
<< "fmod(+5.1, -3.0) = " << std::fmod(5.1,-3) << '\n'
<< "fmod(-5.1, -3.0) = " << std::fmod(-5.1,-3) << '\n';
// special values
std::cout << "fmod(+0.0, 1.0) = " << std::fmod(0, 1) << '\n'
<< "fmod(-0.0, 1.0) = " << std::fmod(-0.0, 1) << '\n'
<< "fmod(5.1, Inf) = " << std::fmod(5.1, INFINITY) << '\n';
// error handling
std::feclearexcept(FE_ALL_EXCEPT);
std::cout << "fmod(+5.1, 0) = " << std::fmod(5.1, 0) << '\n';
if(std::fetestexcept(FE_INVALID))
std::cout << " FE_INVALID raised\n";
}Possible output:
fmod(+5.1, +3.0) = 2.1
fmod(-5.1, +3.0) = -2.1
fmod(+5.1, -3.0) = 2.1
fmod(-5.1, -3.0) = -2.1
fmod(+0.0, 1.0) = 0
fmod(-0.0, 1.0) = -0
fmod(5.1, Inf) = 5.1
fmod(+5.1, 0) = -nan
FE_INVALID raisedSee also
|
(C++11) | computes quotient and remainder of integer division (function) |
|
(C++11)(C++11)(C++11) | signed remainder of the division operation (function) |
|
(C++11)(C++11)(C++11) | signed remainder as well as the three last bits of the division operation (function) |
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