deduction guides for std::deque
Defined in header <deque> | ||
|---|---|---|
template< class InputIt,
class Alloc = std::allocator<typename std::iterator_traits<InputIt>::value_type>>
deque(InputIt, InputIt, Alloc = Alloc())
-> deque<typename std::iterator_traits<InputIt>::value_type, Alloc>;
| (since C++17) |
This deduction guide is provided for deque to allow deduction from an iterator range. This overload only participates in overload resolution if InputIt satisfies LegacyInputIterator and Alloc satisfies Allocator.
Note: the extent to which the library determines that a type does not satisfy LegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type must exist and the expression std::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.
Example
#include <deque>
#include <vector>
int main() {
std::vector<int> v = {1, 2, 3, 4};
// uses explicit deduction guide to deduce std::deque<int>
std::deque x(v.begin(), v.end());
// deduces std::deque<std::vector<int>::iterator>
// first phase of overload resolution for list-initialization selects the candidate
// synthesized from the initializer-list constructor; second phase is not performed and
// deduction guide has no effect
std::deque y{v.begin(), v.end()};
}
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