std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_day)
Defined in header <chrono> | ||
|---|---|---|
constexpr std::chrono::year_month_day operator+(const std::chrono::year_month_day& ymd,
const std::chrono::months& dm) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day operator+(const std::chrono::months& dm,
const std::chrono::year_month_day& ymd) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day operator+(const std::chrono::year_month_day& ymd,
const std::chrono::years& dy) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day operator+(const std::chrono::years& dy,
const std::chrono::year_month_day& ymd) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day operator-(const std::chrono::year_month_day& ymd,
const std::chrono::months& dm) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day operator-(const std::chrono::year_month_day& ymd,
const std::chrono::years& dy) noexcept;
| (since C++20) |
1-2) Adds
dm.count() months to the date represented by ymd. The result has the same day() as ymd and the same year() and month() as std::chrono::year_month(ymd.year(), ymd.month()) + dm.
3-4) Adds
dy.count() years to the date represented by ymd. The result is equivalent to std::chrono::year_month_day(ymd.year() + dy, ymd.month(), ymd.day().
5) Subtracts
dm.count() months from the date represented by ymd. Equivalent to ymd + -dm.
6) Subtracts
dy.count() years from the date represented by ymd. Equivalent to ymd + -dy.Notes
Even if ymd.ok() is true, the resulting year_month_day may not represent a valid date if ymd.day() is 29, 30, or 31.
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