C++ named requirements: Erasable
Specifies that an object of the type can be destroyed by a given Allocator.
Requirements
The type T
is Erasable from the Container X
whose value_type
is identical to T
if, given.
A | an allocator type |
m | an lvalue of type A |
p | the pointer of type T* prepared by the container |
where X::allocator_type
is identical to std::allocator_traits<A>::rebind_alloc<T>
,
the following expression is well-formed:
std::allocator_traits<A>::destroy(m, p);
If X
is not allocator-aware, the term is defined as if A
were std::allocator<T>
, except that no allocator object needs to be created, and user-defined specializations of std::allocator
are not instantiated.
Notes
All standard library containers require that their element type satisfies Erasable.
With the default allocator, this requirement is equivalent to the validity of p->~T()
, which accepts class types with accessible destructors and all scalar types, but rejects array types, function types, reference types, and void.
See Also
CopyInsertable | |
MoveInsertable | |
EmplaceConstructible | |
Destructible |
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