std::literals::chrono_literals::operator""s
Defined in header <chrono> | ||
|---|---|---|
constexpr chrono::seconds operator "" s(unsigned long long secs); | (1) | (since C++14) |
constexpr chrono::duration</*unspecified*/> operator "" s(long double secs); | (2) | (since C++14) |
Forms a std::chrono::duration literal representing seconds.
std::chrono::seconds(secs) std::chrono::seconds
Parameters
| secs | - | the number of seconds |
Return value
The std::chrono::duration literal.
Possible implementation
constexpr std::chrono::seconds operator ""s(unsigned long long s)
{
return std::chrono::seconds(s);
}
constexpr std::chrono::duration<long double> operator ""s(long double s)
{
return std::chrono::duration<long double>(s);
} |
Notes
These operators are declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to these operators can be gained with using namespace std::literals, using namespace std::chrono_literals, and using namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the classes in the chrono library, the corresponding literal operators become visible as well.
std::string also defines operator""s, to represent literal objects of type std::string, but it is a string literal: 10s is ten seconds, but "10"s is a two-character string.
Example
#include <iostream>
#include <chrono>
int main()
{
using namespace std::chrono_literals;
auto halfmin = 30s;
std::cout << "half a minute is " << halfmin.count() << " seconds\n"
<< "a minute and a second is " << (1min + 1s).count() << " seconds\n";
}Output:
half a minute is 30 seconds a minute and a second is 61 seconds
See also
| constructs new duration (public member function of std::chrono::duration<Rep,Period>) |
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