std::log2p1
Defined in header <bit> | ||
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template< class T > constexpr T log2p1(T x) noexcept; | (since C++20) |
If x
is not zero, calculates the number of bits needed to store the value x
, that is, \(1 + \lfloor log_2(x) \rfloor\)1 + floor(log
2(x)). If x
is zero, returns zero.
This overload only participates in overload resolution if T
is an unsigned integer type (that is, unsigned char
, unsigned short
, unsigned int
, unsigned long
, unsigned long long
, or an extended unsigned integer type).
Return value
Zero if x
is zero; otherwise, one plus the base-2 logarithm of x
, with any fractional part discarded.
Example
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