std::copy, std::copy_if
Defined in header <algorithm> | ||
---|---|---|
(1) | ||
template< class InputIt, class OutputIt > OutputIt copy( InputIt first, InputIt last, OutputIt d_first ); | (until C++20) | |
template< class InputIt, class OutputIt > constexpr OutputIt copy( InputIt first, InputIt last, OutputIt d_first ); | (since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt2 copy( ExecutionPolicy&& policy, ForwardIt1 first, ForwardIt1 last, ForwardIt2 d_first ); | (2) | (since C++17) |
(3) | ||
template< class InputIt, class OutputIt, class UnaryPredicate > OutputIt copy_if( InputIt first, InputIt last, OutputIt d_first, UnaryPredicate pred ); | (since C++11) (until C++20) | |
template< class InputIt, class OutputIt, class UnaryPredicate > constexpr OutputIt copy_if( InputIt first, InputIt last, OutputIt d_first, UnaryPredicate pred ); | (since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2, class UnaryPredicate > ForwardIt2 copy_if( ExecutionPolicy&& policy, ForwardIt1 first, ForwardIt1 last, ForwardIt2 d_first, UnaryPredicate pred ); | (4) | (since C++17) |
Copies the elements in the range, defined by [first, last)
, to another range beginning at d_first
.
[first, last)
starting from first and proceeding to last - 1. The behavior is undefined if d_first
is within the range [first, last)
. In this case, std::copy_backward
may be used instead.pred
returns true
. The relative order of the elements that are copied is preserved. The behavior is undefined if the source and the destination ranges overlap.policy
. This overload only participates in overload resolution if std::is_execution_policy_v<std::decay_t<ExecutionPolicy>>
is trueParameters
first, last | - | the range of elements to copy |
d_first | - | the beginning of the destination range. |
policy | - | the execution policy to use. See execution policy for details. |
pred | - | unary predicate which returns true for the required elements. The expression |
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator. |
||
-OutputIt must meet the requirements of LegacyOutputIterator. |
||
-ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator. |
||
-UnaryPredicate must meet the requirements of Predicate. |
Return value
Output iterator to the element in the destination range, one past the last element copied.
Complexity
- 1-2) Exactly
(last - first)
assignments - 3-4) Exactly
(last - first)
applications of the predicate, between0
and(last - first)
assignments (assignment for every element for which predicate is equal to true, dependent on predicate and input data)
For the overloads with an ExecutionPolicy, there may be a performance cost if ForwardIt1
's value_type is not MoveConstructible.
Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies,std::terminate
is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory,
std::bad_alloc
is thrown.
Notes
In practice, implementations of std::copy
avoid multiple assignments and use bulk copy functions such as std::memmove
if the value type is TriviallyCopyable.
When copying overlapping ranges, std::copy
is appropriate when copying to the left (beginning of the destination range is outside the source range) while std::copy_backward
is appropriate when copying to the right (end of the destination range is outside the source range).
Possible implementation
First version |
---|
template<class InputIt, class OutputIt> OutputIt copy(InputIt first, InputIt last, OutputIt d_first) { while (first != last) { *d_first++ = *first++; } return d_first; } |
Second version |
template<class InputIt, class OutputIt, class UnaryPredicate> OutputIt copy_if(InputIt first, InputIt last, OutputIt d_first, UnaryPredicate pred) { while (first != last) { if (pred(*first)) *d_first++ = *first; first++; } return d_first; } |
Example
The following code uses copy to both copy the contents of one vector to another and to display the resulting vector:
#include <algorithm> #include <iostream> #include <vector> #include <iterator> #include <numeric> int main() { std::vector<int> from_vector(10); std::iota(from_vector.begin(), from_vector.end(), 0); std::vector<int> to_vector; std::copy(from_vector.begin(), from_vector.end(), std::back_inserter(to_vector)); // or, alternatively, // std::vector<int> to_vector(from_vector.size()); // std::copy(from_vector.begin(), from_vector.end(), to_vector.begin()); // either way is equivalent to // std::vector<int> to_vector = from_vector; std::cout << "to_vector contains: "; std::copy(to_vector.begin(), to_vector.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; }
Output:
to_vector contains: 0 1 2 3 4 5 6 7 8 9
See also
copies a range of elements in backwards order (function template) |
|
creates a copy of a range that is reversed (function template) |
|
(C++11) | copies a number of elements to a new location (function template) |
copy-assigns the given value to every element in a range (function template) |
|
copies a range of elements omitting those that satisfy specific criteria (function template) |
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