std::chrono::operator+, std::chrono::operator- (std::chrono::weekday)

constexpr std::chrono::weekday operator+(const std::chrono::weekday& wd, const std::chrono::days& d) noexcept;	(1)	(since C++20)
constexpr std::chrono::weekday operator+(const std::chrono::days& d, const std::chrono::weekday& wd) noexcept;	(2)	(since C++20)
constexpr std::chrono::weekday operator-(const std::chrono::weekday& wd, const std::chrono::days& d) noexcept;	(3)	(since C++20)
constexpr std::chrono::days operator-(const std::chrono::weekday& wd1, const std::chrono::weekday& wd2) noexcept;	(4)	(since C++20)

1-2) Adds d.count() days to wd. The weekday value held in the result is computed by first evaluating static_cast<long long>(unsigned(wd)) + d.count() and reducing it modulo 7 to an integer in the range [0, 6].

3) Subtracts d.count() days from wd. Equivalent to return wd + -d;

4) If wd1.ok() and wd2.ok() are both true, returns a std::chrono::days value d such that d.count() is in the range [0, 6] and wd2 + d == wd1. Otherwise the returned value is unspecified.

Return value

1-3) A std::chrono::weekday holding a weekday value calculated as described above.

4) A std::chrono::days representing the distance between wd1 and wd2.

Notes

As long as the computation doesn't overflow, (1-3) always return a valid weekday even if wd.ok() is false.

operator++operator++(int)operator--operator--(int)	increments or decrements the weekday (public member function)
operator+=operator-=	adds or subtracts a number of days (public member function)

std::chrono::operator+, std::chrono::operator- (std::chrono::weekday)

Return value

Notes

Example

See also