std::remainder, std::remainderf, std::remainderl
Defined in header <cmath> | ||
|---|---|---|
float remainder ( float x, float y ); float remainderf( float x, float y ); | (1) | (since C++11) |
double remainder ( double x, double y ); | (2) | (since C++11) |
long double remainder ( long double x, long double y ); long double remainderl( long double x, long double y ); | (3) | (since C++11) |
Promoted remainder ( Arithmetic1 x, Arithmetic2 y ); | (4) | (since C++11) |
x/y.double. If any other argument is long double, then the return type is long double, otherwise it is double.The IEEE floating-point remainder of the division operation x/y calculated by this function is exactly the value x - n*y, where the value n is the integral value nearest the exact value x/y. When |n-x/y| = ½, the value n is chosen to be even.
In contrast to std::fmod(), the returned value is not guaranteed to have the same sign as x.
If the returned value is 0, it will have the same sign as x.
Parameters
| x, y | - | values of floating-point or integral types |
Return value
If successful, returns the IEEE floating-point remainder of the division x/y as defined above.
If a domain error occurs, an implementation-defined value is returned (NaN where supported).
If a range error occurs due to underflow, the correct result is returned.
If y is zero, but the domain error does not occur, zero is returned.
Error handling
Errors are reported as specified in math_errhandling.
Domain error may occur if y is zero.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- The current rounding mode has no effect.
-
FE_INEXACTis never raised, the result is always exact. - If
xis ±∞ andyis not NaN, NaN is returned andFE_INVALIDis raised - If
yis ±0 andxis not NaN, NaN is returned andFE_INVALIDis raised - If either argument is NaN, NaN is returned
Notes
POSIX requires that a domain error occurs if x is infinite or y is zero.
std::fmod, but not std::remainder is useful for doing silent wrapping of floating-point types to unsigned integer types: (0.0 <= (y = std::fmod( std::rint(x), 65536.0 )) ? y : 65536.0 + y) is in the range [-0.0 .. 65535.0], which corresponds to unsigned short, but std::remainder(std::rint(x), 65536.0) is in the range [-32767.0, +32768.0], which is outside of the range of signed short.
Example
#include <iostream>
#include <cmath>
#include <cfenv>
#pragma STDC FENV_ACCESS ON
int main()
{
std::cout << "remainder(+5.1, +3.0) = " << std::remainder(5.1,3) << '\n'
<< "remainder(-5.1, +3.0) = " << std::remainder(-5.1,3) << '\n'
<< "remainder(+5.1, -3.0) = " << std::remainder(5.1,-3) << '\n'
<< "remainder(-5.1, -3.0) = " << std::remainder(-5.1,-3) << '\n';
// special values
std::cout << "remainder(-0.0, 1.0) = " << std::remainder(-0.0, 1) << '\n'
<< "remainder(5.1, Inf) = " << std::remainder(5.1, INFINITY) << '\n';
// error handling
std::feclearexcept(FE_ALL_EXCEPT);
std::cout << "remainder(+5.1, 0) = " << std::remainder(5.1, 0) << '\n';
if(fetestexcept(FE_INVALID))
std::cout << " FE_INVALID raised\n";
}Possible output:
remainder(+5.1, +3.0) = -0.9
remainder(-5.1, +3.0) = 0.9
remainder(+5.1, -3.0) = -0.9
remainder(-5.1, -3.0) = 0.9
remainder(-0.0, 1.0) = -0
remainder(5.1, Inf) = 5.1
remainder(+5.1, 0) = -nan
FE_INVALID raisedSee also
|
(C++11) | computes quotient and remainder of integer division (function) |
|
(C++11)(C++11) | remainder of the floating point division operation (function) |
|
(C++11)(C++11)(C++11) | signed remainder as well as the three last bits of the division operation (function) |
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