std::isspace(std::locale)

Defined in header <locale>
template< class charT >
bool isspace( charT ch, const locale& loc );

Checks if the given character is classified as a whitespace character by the given locale's ctype facet.

Parameters

ch - character
loc - locale

Return value

Returns true if the character is classified as a whitespace character, false otherwise.

Possible implementation

template< class charT >
bool isspace( charT ch, const std::locale& loc ) {
    return std::use_facet<std::ctype<charT>>(loc).is(std::ctype_base::space, ch);
}

Example

Demonstrates the use of isspace() with different locales (OS-specific).

#include <iostream>
#include <locale>
 
void try_with(wchar_t c, const char* loc)
{
    std::wcout << "isspace('" << c << "', locale(\"" << loc << "\")) returned "
               << std::boolalpha << std::isspace(c, std::locale(loc)) << '\n';
}
 
int main()
{
    const wchar_t EM_SPACE = L'\u2003'; // Unicode character 'EM SPACE'
    try_with(EM_SPACE, "C");
    try_with(EM_SPACE, "en_US.UTF8");
}

Output:

isspace(' ', locale("C")) returned false
isspace(' ', locale("en_US.UTF8")) returned true

See also

checks if a character is a space character
(function)
checks if a wide character is a space character
(function)

© cppreference.com
Licensed under the Creative Commons Attribution-ShareAlike Unported License v3.0.
http://en.cppreference.com/w/cpp/locale/isspace