std::allocator<T>::deallocate

void deallocate( T* p, std::size_t n );

Deallocates the storage referenced by the pointer p, which must be a pointer obtained by an earlier call to allocate().

The argument n must be equal to the first argument of the call to allocate() that originally produced p; otherwise, the behavior is undefined.

Calls ::operator delete(void*) or ::operator delete(void*, std::align_val_t) (since C++17), but it is unspecified when and how it is called.

p	-	pointer obtained from `allocate()`
n	-	number of objects earlier passed to `allocate()`

(none).

allocate	allocates uninitialized storage (public member function)
deallocate [static]	deallocates storage using the allocator (public static member function of `std::allocator_traits<Alloc>`)