tf.math.unsorted_segment_sqrt_n
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Computes the sum along segments of a tensor divided by the sqrt(N).
tf.math.unsorted_segment_sqrt_n( data, segment_ids, num_segments, name=None )
Read the section on segmentation for an explanation of segments.
This operator is similar to the tf.math.unsorted_segment_sum
operator. Additionally to computing the sum over segments, it divides the results by sqrt(N).
\(output_i = 1/sqrt(N_i) \sum_{j...} data[j...]\) where the sum is over tuples j...
such that segment_ids[j...] == i
with \N_i\ being the number of occurrences of id \i\.
If there is no entry for a given segment ID i
, it outputs 0.
Note that this op only supports floating point and complex dtypes, due to tf.sqrt only supporting these types.
If the given segment ID i
is negative, the value is dropped and will not be added to the sum of the segment.
Args | |
---|---|
data | A Tensor with floating point or complex dtype. |
segment_ids | An integer tensor whose shape is a prefix of data.shape . |
num_segments | An integer scalar Tensor . The number of distinct segment IDs. |
name | A name for the operation (optional). |
Returns | |
---|---|
A Tensor . Has same shape as data, except for the first segment_ids.rank dimensions, which are replaced with a single dimension which has size num_segments . |
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Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r2.4/api_docs/python/tf/math/unsorted_segment_sqrt_n