parse method
num parse(Parses a string containing a number literal into a number.
The method first tries to read the input
as integer (similar to int.parse without a radix). If that fails, it tries to parse the input
as a double (similar to double.parse). If that fails, too, it invokes onError
with input
, and the result of that invocation becomes the result of calling parse
.
If no onError
is supplied, it defaults to a function that throws a FormatException.
For any number n
, this function satisfies identical(n, num.parse(n.toString()))
(except when n
is a NaN double
with a payload).
Source
static num parse(String input, [num onError(String input)]) { String source = input.trim(); // TODO(lrn): Optimize to detect format and result type in one check. num result = int.parse(source, onError: _returnIntNull); if (result != null) return result; result = double.parse(source, _returnDoubleNull); if (result != null) return result; if (onError == null) throw new FormatException(input); return onError(input); }
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https://api.dartlang.org/stable/1.24.3/dart-core/num/parse.html