numpy.intersect1d

numpy.intersect1d(ar1, ar2, assume_unique=False, return_indices=False) [source]

Find the intersection of two arrays.

Return the sorted, unique values that are in both of the input arrays.

Parameters

ar1, ar2array_like

Input arrays. Will be flattened if not already 1D.

assume_uniquebool

If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.

return_indicesbool

If True, the indices which correspond to the intersection of the two arrays are returned. The first instance of a value is used if there are multiple. Default is False.

New in version 1.15.0.

Returns

intersect1dndarray

Sorted 1D array of common and unique elements.

comm1ndarray

The indices of the first occurrences of the common values in ar1. Only provided if return_indices is True.

comm2ndarray

The indices of the first occurrences of the common values in ar2. Only provided if return_indices is True.

See also

numpy.lib.arraysetops

Module with a number of other functions for performing set operations on arrays.

Examples

>>> np.intersect1d([1, 3, 4, 3], [3, 1, 2, 1])
array([1, 3])

To intersect more than two arrays, use functools.reduce:

>>> from functools import reduce
>>> reduce(np.intersect1d, ([1, 3, 4, 3], [3, 1, 2, 1], [6, 3, 4, 2]))
array([3])

To return the indices of the values common to the input arrays along with the intersected values:

>>> x = np.array([1, 1, 2, 3, 4])
>>> y = np.array([2, 1, 4, 6])
>>> xy, x_ind, y_ind = np.intersect1d(x, y, return_indices=True)
>>> x_ind, y_ind
(array([0, 2, 4]), array([1, 0, 2]))
>>> xy, x[x_ind], y[y_ind]
(array([1, 2, 4]), array([1, 2, 4]), array([1, 2, 4]))