pandas.core.groupby.SeriesGroupBy.nlargest

SeriesGroupBy.nlargest

Return the largest n elements.

Parameters:	n : int Return this many descending sorted values keep : {‘first’, ‘last’}, default ‘first’ Where there are duplicate values: - first : take the first occurrence. - last : take the last occurrence.
Returns:	top_n : Series The n largest values in the Series, in sorted order

See also

Series.nsmallest

Notes

Faster than .sort_values(ascending=False).head(n) for small n relative to the size of the Series object.

Examples

>>> import pandas as pd
>>> import numpy as np
>>> s = pd.Series(np.random.randn(10**6))
>>> s.nlargest(10)  # only sorts up to the N requested
219921    4.644710
82124     4.608745
421689    4.564644
425277    4.447014
718691    4.414137
43154     4.403520
283187    4.313922
595519    4.273635
503969    4.250236
121637    4.240952
dtype: float64