combineLatest
function
stable
Combines multiple Observables to create an Observable whose values are calculated from the latest values of each of its input Observables.
combineLatest<O extends ObservableInput<any>, R>(...args: any[]): Observable<R> | Observable<ObservedValueOf<O>[]>
Parameters
args | Type: |
Returns
Observable<R> | Observable<ObservedValueOf<O>[]>
: An Observable of projected values from the most recent values from each input Observable, or an array of the most recent values from each input Observable.
Description
Whenever any input Observable emits a value, it computes a formula using the latest values from all the inputs, then emits the output of that formula.
combineLatest
combines the values from all the Observables passed in the observables array. This is done by subscribing to each Observable in order and, whenever any Observable emits, collecting an array of the most recent values from each Observable. So if you pass n
Observables to this operator, the returned Observable will always emit an array of n
values, in an order corresponding to the order of the passed Observables (the value from the first Observable will be at index 0 of the array and so on).
Static version of combineLatest
accepts an array of Observables. Note that an array of Observables is a good choice, if you don't know beforehand how many Observables you will combine. Passing an empty array will result in an Observable that completes immediately.
To ensure the output array always has the same length, combineLatest
will actually wait for all input Observables to emit at least once, before it starts emitting results. This means if some Observable emits values before other Observables started emitting, all these values but the last will be lost. On the other hand, if some Observable does not emit a value but completes, resulting Observable will complete at the same moment without emitting anything, since it will now be impossible to include a value from the completed Observable in the resulting array. Also, if some input Observable does not emit any value and never completes, combineLatest
will also never emit and never complete, since, again, it will wait for all streams to emit some value.
If at least one Observable was passed to combineLatest
and all passed Observables emitted something, the resulting Observable will complete when all combined streams complete. So even if some Observable completes, the result of combineLatest
will still emit values when other Observables do. In case of a completed Observable, its value from now on will always be the last emitted value. On the other hand, if any Observable errors, combineLatest
will error immediately as well, and all other Observables will be unsubscribed.
Examples
Combine two timer Observables
import { combineLatest, timer } from 'rxjs'; const firstTimer = timer(0, 1000); // emit 0, 1, 2... after every second, starting from now const secondTimer = timer(500, 1000); // emit 0, 1, 2... after every second, starting 0,5s from now const combinedTimers = combineLatest([firstTimer, secondTimer]); combinedTimers.subscribe(value => console.log(value)); // Logs // [0, 0] after 0.5s // [1, 0] after 1s // [1, 1] after 1.5s // [2, 1] after 2s
Combine a dictionary of Observables
import { combineLatest, of } from 'rxjs'; import { delay, startWith } from 'rxjs/operators'; const observables = { a: of(1).pipe(delay(1000), startWith(0)), b: of(5).pipe(delay(5000), startWith(0)), c: of(10).pipe(delay(10000), startWith(0)) }; const combined = combineLatest(observables); combined.subscribe(value => console.log(value)); // Logs // {a: 0, b: 0, c: 0} immediately // {a: 1, b: 0, c: 0} after 1s // {a: 1, b: 5, c: 0} after 5s // {a: 1, b: 5, c: 10} after 10s
Combine an array of Observables
import { combineLatest, of } from 'rxjs'; import { delay, startWith } from 'rxjs/operators'; const observables = [1, 5, 10].map( n => of(n).pipe( delay(n * 1000), // emit 0 and then emit n after n seconds startWith(0), ) ); const combined = combineLatest(observables); combined.subscribe(value => console.log(value)); // Logs // [0, 0, 0] immediately // [1, 0, 0] after 1s // [1, 5, 0] after 5s // [1, 5, 10] after 10s
Use map operator to dynamically calculate the Body-Mass Index
import { combineLatest, of } from 'rxjs'; import { map } from 'rxjs/operators'; const weight = of(70, 72, 76, 79, 75); const height = of(1.76, 1.77, 1.78); const bmi = combineLatest([weight, height]).pipe( map(([w, h]) => w / (h * h)), ); bmi.subscribe(x => console.log('BMI is ' + x)); // With output to console: // BMI is 24.212293388429753 // BMI is 23.93948099205209 // BMI is 23.671253629592222
Overloads
combineLatest(arg: T): Observable<unknown>
You have passed any
here, we can't figure out if it is an array or an object, so you're getting unknown
. Use better types.
Parameters
arg | Something typed as |
Returns
Observable<unknown>
combineLatest(sources: []): Observable<never>
Parameters
sources | Type: |
Returns
Observable<never>
combineLatest(sources: readonly any[]): Observable<A>
Parameters
sources | Type: |
Returns
Observable<A>
combineLatest(sources: readonly any[], resultSelector: (...values: A) => R, scheduler: SchedulerLike): Observable<R>
Deprecation Notes
The scheduler
parameter will be removed in v8. Use scheduled
and combineLatestAll
. Details: https://rxjs.dev/deprecations/scheduler-argument
Parameters
sources | Type: |
resultSelector | Type: |
scheduler | Type: |
Returns
Observable<R>
combineLatest(sources: readonly any[], resultSelector: (...values: A) => R): Observable<R>
Parameters
sources | Type: |
resultSelector | Type: |
Returns
Observable<R>
combineLatest(sources: readonly any[], scheduler: SchedulerLike): Observable<A>
Deprecation Notes
The scheduler
parameter will be removed in v8. Use scheduled
and combineLatestAll
. Details: https://rxjs.dev/deprecations/scheduler-argument
Parameters
sources | Type: |
scheduler | Type: |
Returns
Observable<A>
combineLatest(...sources: any[]): Observable<A>
Deprecation Notes
Pass an array of sources instead. The rest-parameters signature will be removed in v8. Details: https://rxjs.dev/deprecations/array-argument
Parameters
sources | Type: |
Returns
Observable<A>
combineLatest(...sourcesAndResultSelectorAndScheduler: [any, (...values: A) => R, SchedulerLike]): Observable<R>
Deprecation Notes
The scheduler
parameter will be removed in v8. Use scheduled
and combineLatestAll
. Details: https://rxjs.dev/deprecations/scheduler-argument
Parameters
sourcesAndResultSelectorAndScheduler | Type: |
Returns
Observable<R>
combineLatest(...sourcesAndResultSelector: [any, (...values: A) => R]): Observable<R>
Deprecation Notes
Pass an array of sources instead. The rest-parameters signature will be removed in v8. Details: https://rxjs.dev/deprecations/array-argument
Parameters
sourcesAndResultSelector | Type: |
Returns
Observable<R>
combineLatest(...sourcesAndScheduler: [any, SchedulerLike]): Observable<A>
Deprecation Notes
The scheduler
parameter will be removed in v8. Use scheduled
and combineLatestAll
. Details: https://rxjs.dev/deprecations/scheduler-argument
Parameters
sourcesAndScheduler | Type: |
Returns
Observable<A>
combineLatest(sourcesObject: { [x: string]: never; }): Observable<never>
Parameters
sourcesObject | Type: |
Returns
Observable<never>
combineLatest(sourcesObject: T): Observable<{
[K in keyof T]: ObservedValueOf<T[K]>;
}>
Parameters
sourcesObject | Type: |
Returns
Observable<{ [K in keyof T]: ObservedValueOf<T[K]>; }>
See Also
© 2015–2021 Google, Inc., Netflix, Inc., Microsoft Corp. and contributors.
Code licensed under an Apache-2.0 License. Documentation licensed under CC BY 4.0.
https://rxjs.dev/api/index/function/combineLatest